CSC/ECE 506 Spring 2010/ch 3 yl: Difference between revisions
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Let S1 -> S2 denote statement S1 executes before S2. | Let S1 -> S2 denote statement S1 executes before S2. | ||
Then, we further define three statement dependences: | Then, we further define three statement dependences: | ||
*S1 ->T S2 denotes true dependence: S1 -> S2, and S1 writes to a location that is read by S2. S1 is the producer of data that is read by the consumer (S2). | *S1 ->T S2 denotes true dependence: S1 -> S2, and S1 writes to a location that is read by S2. S1 is the producer of data that is read by the consumer (S2). | ||
*S1 ->A S2 denotes anti dependence: | |||
====Loop-independent==== | ====Loop-independent==== |
Revision as of 20:32, 20 February 2010
Supplement to Chapter 3: Support for parallel-programming models. Discuss how DOACROSS, DOPIPE, DOALL, etc. are implemented in packages such as Posix threads, Intel Thread Building Blocks, OpenMP 2.0 and 3.0.
Parallel-programming models
Loop-independent vs. loop-carried dependences
Before performing the three kinds of parallelism analysis, we need to discuss about loop-dependence analysis first.
Statement dependences
To discuss code analysis, let's define the framework as follows. Let S denote a statement in the source code. Let [] denote loop iteration space. Let S1 -> S2 denote statement S1 executes before S2. Then, we further define three statement dependences:
- S1 ->T S2 denotes true dependence: S1 -> S2, and S1 writes to a location that is read by S2. S1 is the producer of data that is read by the consumer (S2).
- S1 ->A S2 denotes anti dependence:
Loop-independent
Loop-carried dependences
DOALL
for i:=2:N-1 do A(i):=[A(i-1) + A(i) + A(i+1)]/3; next i; forall i:=2:N-1 do A(i):=[A(i-1) + A(i) + A(i+1)]/3;
for (i=2; i<=n; i+=2) s: a[i] = a[i-2]; for (i=3; i<=n; i+=2) s: a[i] = a[i-2];
DOACROSS
for (i=1; i<=N; i++) { S: a[i] = a[i-1] + b[i] * c[i];}
for (i=1; i<=N; i++) { S1: temp[i] = b[i] * c[i];} for (i=1; i<=N; i++) { S2: a[i] = a[i-1] + temp[i];}
post(0); for (i=1; i<=N; i++) { S1: temp[i] = b[i] * c[i];} wait(i-1); S2: a[i] = a[i-1] + temp[i]; post(i);}