CSC/ECE 506 Spring 2015/37 mr: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
|||
(6 intermediate revisions by the same user not shown) | |||
Line 10: | Line 10: | ||
The code to parallelize: | The code to parallelize: | ||
int main() | int main() | ||
{ | { | ||
omp_set_num_threads(6); | |||
long sum = 1; | |||
int size = 5; | |||
int i, j, rowsum; | |||
int first[5][5] = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25} }; | |||
for ( i = 0 ; i < size ; i++ ){ | |||
rowsum = 0; | |||
for ( j = 0 ; j < size ; j++ ){ | |||
rowsum = rowsum + first[i][j]; | |||
} | |||
sum = rowsum*sum; | |||
} | |||
printf("sum: %d\n", sum); | |||
return 0; | |||
} | } | ||
== Answer 1 == | == Answer 1 == | ||
int main() | int main() | ||
{ | { | ||
omp_set_num_threads(6); | |||
long sum = 1; | |||
int size = 5; | int size = 5; | ||
int i, j; | int i, j, rowsum; | ||
#pragma omp parallel shared(rowsum, i, sum) private(j) | |||
{ | |||
int first[5][5] = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25} }; | int first[5][5] = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25} }; | ||
#pragma omp for | |||
#pragma omp | |||
for ( i = 0 ; i < size ; i++ ){ | for ( i = 0 ; i < size ; i++ ){ | ||
rowsum = 0; | |||
for ( j = 0 ; j < size ; j++ ){ | for ( j = 0 ; j < size ; j++ ){ | ||
rowsum = rowsum + first[i][j]; | |||
} | } | ||
#pragma omp critical | |||
sum = rowsum*sum; | |||
} | } | ||
printf(" | } | ||
printf("sum: %d\n", sum); | |||
return 0; | |||
} | } | ||
Latest revision as of 04:49, 3 February 2015
A (simple) Introduction to OpenMP
How to run the samples on EOS
gcc -fopenmp hello.c -o hello
Question 1
Parallelize the following code using OpenMP
The code to parallelize:
int main() { omp_set_num_threads(6); long sum = 1; int size = 5; int i, j, rowsum; int first[5][5] = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25} }; for ( i = 0 ; i < size ; i++ ){ rowsum = 0; for ( j = 0 ; j < size ; j++ ){ rowsum = rowsum + first[i][j]; } sum = rowsum*sum; } printf("sum: %d\n", sum); return 0; }
Answer 1
int main() { omp_set_num_threads(6); long sum = 1; int size = 5; int i, j, rowsum; #pragma omp parallel shared(rowsum, i, sum) private(j) { int first[5][5] = { { 1, 2, 3, 4, 5 }, { 6, 7, 8, 9, 10 }, { 11, 12, 13, 14, 15 }, {16, 17, 18, 19, 20}, {21, 22, 23, 24, 25} }; #pragma omp for for ( i = 0 ; i < size ; i++ ){ rowsum = 0; for ( j = 0 ; j < size ; j++ ){ rowsum = rowsum + first[i][j]; } #pragma omp critical sum = rowsum*sum; } } printf("sum: %d\n", sum); return 0; }
Question 2
Parallelize the code below using loop distribution
for (i=0; i<n; i++) { S1: a[i] = b[i-1] * a[i+1]; S2: b[i] = b[i] * 3; S3: c[i] = .2 * (c[i-1] * c[i]); }
After loop distribution
for(i=0; i < n; i++) S1: a[i] = b[i-1] * a[i+1]; for(i=0; i < n; i++) S3: c[i] = .2* c[i-1] * c[i]; for(i=0; i < n; i++) S2: b[i] = b[i] * 3;
Now write the parallelized code in openMP using C++
#pragma omp parallel shared(a,b,c)private(i) { #pragma omp sections nowait { #pragma omp section for(i=0; i < n; i++) a[i] = b[i-1] * a[i+1]; #pragma omp section for(i=0; i<n; i++) c[i] = .2* c[i-1]*c[i]; #pragma omp section for(i=0; i < n; i++) b[i] = b[i] * 3; }//end omp sections } //end omp parallel